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Number of moles of KI required to prepar...

Number of moles of `KI` required to prepare `0.4` moles of `K_(2)Hgl_(4)`, when `HgCl_(2)` reacts with `Kl`

A

0.4 moles of KI

B

0.8 moles of KI

C

1.6 moles of KI

D

3.2 moles of KI

Text Solution

Verified by Experts

The correct Answer is:
C
`HgCI_(2) +4KI rarr K_(2)HgI_(4) +2KCI`
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