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1.5g CdCl(2) was formed to contain 0.9g ...

1.5g `CdCl_(2)` was formed to contain 0.9g Cd. Calculate the atmic weight of Cd.

A

118

B

112

C

`106.5`

D

`53.25`

Text Solution

Verified by Experts

The correct Answer is:
C
`%Cd` in `CdCl_(2)(60%), % Cl_(2)` in `CdCl_(2)(40%)`
40% has -At wt 71
`60% -106.5`
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