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3.0gms of an organic compound on combust...

`3.0gms` of an organic compound on combustion give `8.8 gm` of `CO_(2)` and `5.4gm` of water. The empirical formula of the compound is

A

`CH_(3)`

B

`C_(2)H_(4)`

C

`C_(2)H_(2)`

D

`C_(2)H_(6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(x)H_(y)+ (x+(y)/(4)) O_(2) rarr xCO_(2) +(y)/(2) H_(2)O`
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