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A solution containing 0.2 mole of ferric...

A solution containing `0.2` mole of ferric chloride is allowed to react with `0.24` mole of sodium hydroxide. The correct statement for this reaction is

A

Limiting reagent for this reaction is `NaOH`

B

`0.08` moles of `Fe(OH_(3))` is formed

C

`0.12` mole of `FeCI_(3)` is left unreacted

D

All the above

Text Solution

Verified by Experts

The correct Answer is:
B
`FeCl_(3) +3NaOh rarr Fe(OH)_(3) +3NaCl`
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Knowledge Check

  • 1 mole of sodium chloride contains

    A
    `6.022 xx 10^(22)` atoms
    B
    `6.022 xx 10^(23)` atoms
    C
    `6.022 xx 10^(24)` atoms
    D
    None of these

  • How many moleculs would be there in 0.01 moles of sodium hydroxide?

    A
    `6.023 xx 10^(23)`
    B
    `6.023 xx 10^(21)`
    C
    `6.023 xx 10^(22)`
    D
    `6.023 xx 10^(20)`

  • If 0.7 moles of Barium Chloride is treated with 0.4 mole of potassium sulphate, number of moles of barium sulphate formed are

    A
    0.7
    B
    0.4
    C
    0.35
    D
    0.2

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