100 mL of x M `KMnO_(4)` is requried oxidise 200 mL of 0.2 M ferric oxalate in acidic medium what is the normality of `KMnO_(4)`?

Options

A. `0.0075`
B. `0.005`
C. `0.01`
D. `0.015`

Answer

A

Explanation

`MnO_(4)^(-) +I^(-) rarr MnO_(2) +I_(2)`
No: of milli eq of `MnO_(4)^(-) = 0.02 xx 3 xx 250 = 15`
No: of milli eq. of `I_(2) = 0.1 xx 2 xx 250 = 25`
Here `Mno_(4)^(-)` is limiting reagent.
`:.` No of milli eq. of `I_(2)` formed `=15`
`:.` No. of milli eq of `I_(2)` formed `=(15)/(1000) = 0.015`
`:.` No of milli moles of `I_(2)` formed `=(0.015)/(2) = 0.0075`