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The oxidation state of the most electron...

The oxidation state of the most electronegative atom in each of the product is
`H_(2) +O_(2) rarr H_(2)O_(2) +H_(2)O`

A

`-2,-2`

B

`+1,-2`

C

`+2,-1`

D

`-1,-2`

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)+O_(2) rarr H_(2) overset(-1)(O_(2)) +H_(2) overset(-2)(O)`
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