A gaseous hydrocarbon gives upon combustion `0.72g` of water and `3.08g` of `CO_(2)`. The empirical formula of the hydrocarbon is

Options

A. `C_(3)H_(4)`
B. `C_(6)H_(5)`
C. `C_(7)H_(8)`
D. `C_(2)H_(4)`

Answer

C

Explanation

`{:(C_(x)H_(y)+,(x+(y)/(4))O_(2)rarr,xCO_(2)+,(y)/(2)H_(2)O),(wt,,3.08g,0.72g),("moles",,0.07,0.04),((x)/(y)=(7)/(8),,,):}`