A hydrocarbon contains `10.5 g` of carbon per gram of hydrogen. `1 L` of vapour of the hydrocarbon at `127^(@)C` and 1 atm pressure weighs `2.8 g`. Find the molecular formula of the hydrocarbon.

Options

A. `C_(7)H_(8)`
B. `C_(6)H_(10)`
C. `C_(7)H_(6)`
D. `C_(6)H_(12)`

Answer

A

Explanation

Volume at `NTP = (p_(1) xx V_(1))/(T_(1)) xx (T_(2))/(P_(2))`
`= (1 xx 1)/(400) xx (273)/(1) = (273)/(400)` litre
`:' (273)/(400)` litre weights 2.8 g at STP.
`:' 22.4` litres (1 mole) . Weights =`(2.8 xx 400)/(273) xx 22.4g = 91.8974 ~~ 92 g`