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A hydrocarbon 'X' have 81% of carbon. Vo...

A hydrocarbon 'X' have `81%` of carbon. Volume of `CO_(2)` liberated at 298K and 76 cm of Hg when `0.55gm` of 'x' undergoes combustion

A

`0.90l`

B

`11.09l`

C

`1.89l`

D

`1.09l`

Text Solution

Verified by Experts

The correct Answer is:
A
`100g ------gt 81g`
`0.55 g ------gt 0.4455g`
`12g rarr 24.4658l (V =(nRT)/(P) = (1 xx 0.0821 xx 298)/(1))`
`0.4455 g rarr 0.908l`
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