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50.0 kg of N(2)(g) and 10.0 kg of H(2)(g...

50.0 kg of `N_(2)(g)` and 10.0 kg of `H_(2)(g)` are mixed to produce `NH_(3)(g)`. Calculate the `NH_(3)(g)` formed. Identify the limiting reagent in the production of `NH_(3)` in this situation.

A

`H_(2),56.67kg`

B

`H_(2),13.1kg`

C

`H_(2),1.56kg`

D

`H_(2),36.2kg`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)+3H_(2) rarr 2NH_(3)`
`(H_(2)` is limiting reagent)
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