One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

Options

A. `+1`
B. `+2`
C. `+3`
D. `+5`

Answer

C

Explanation

If 1 mole hydrazine lost 10 moles of electrons than nitrogen oxidation state changes from `-2` to `+3`
`N_(2)^(2-) rarr 2N^(+a) +10e^(-)`
`2a - (-4) = 10 rArr a = +3`