In the reaction, `A^(n+)+MnO_(4)^(-) rarr A^(5) +Mn^(2+)` if 0`0.05` mole of `A^(n+)` is oxidized by `0.02` mole of `MnO_(4)^(-)`, the value of 'n' is

Options

A. 1
B. 2
C. 3
D. 4

Answer

C

Explanation

`0.05` moles `A^(n+)` oxidized by `0.02` moles `MnO_(4)^(-5)` moles `A^(n+)` oxidized by 2 mole `MnO_(4)^(-)` balanced redox equation is
`5A^(n+) +MnO_(4)^(-) rarr 5A^(5+) +2Mn^(+2)`
In a reodx reaxtion, increase in O.N. of one atom =decrease in O.N of another atom
`//5(5-n =10, 5-n = 2, n = 3)`