1 mole of equimolar mixture of ferric oxalate and ferrous oxalate requres x mole of `KMnO_(4)` in acidic medium for complete oxidation. X is:

Options

A. 0.5 mole
B. 0.9 mole
C. 1.2 mole
D. 4.5 mole

Answer

B

Explanation

`(n = 6) (n = 5)`
`+6CO_(2) +H_(2)O`
`FeC_(2)O_(4) +MnO_(4)^(-) +H^(+) rarr Fe^(3+)`
`(n = 3) (n = 5)`
`+2CO_(2) + H_(2)O`
Total equivalents of
`(Fe_(2) (C_(2)O_(4))_(3)+FeC_(2)O_(4))`
= equivalents of `KMnO_(4) :. 0.5 xx 6 + 0.5 xx 3 = x xx 5` moles of `KMnO_(4) = x = 0.9`