Hydrogen gas is prepared in the laborato...

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place
`Zn+2HClrarrZnCl_(2)+H_(2)`
Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3u

`11.35L`

`22.7L`

`16.42L`

`11L`

Text Solution

Verified by Experts

The correct Answer is:

From the equation. `63.5g` of zinc liberates `22.7` litre of hydrogen. So `32.65g` of zinc will liberate
`32.65g Zn xx (22.7 L H_(2))/(65.3g Zn) = (22.7)/(2)L = 11.35L`

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