The number of molecules present in 4.4g of `CO_(2)` gas is

Options

A. `6.023 xx 10^(23)`
B. `5.023 xx 10^(23)`
C. `6.023 xx 10^(24)`
D. `6.023 xx 10^(22)`

Explanation

To find the number of molecules present in 4.4 g of \( CO_2 \) gas, we can follow these steps:

### Step 1: Calculate the molar mass of \( CO_2 \)
The molar mass of \( CO_2 \) can be calculated by adding the atomic masses of carbon (C) and oxygen (O):
- Atomic mass of Carbon (C) = 12 g/mol
- Atomic mass of Oxygen (O) = 16 g/mol

Since \( CO_2 \) has one carbon atom and two oxygen atoms, the molar mass is:
\[ \text{Molar mass of } CO_2 = 12 + (2 \times 16) = 12 + 32 = 44 \text{ g/mol} \]

### Step 2: Calculate the number of moles of \( CO_2 \) in 4.4 g
Using the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
we can substitute the values:
\[ \text{Number of moles} = \frac{4.4 \text{ g}}{44 \text{ g/mol}} = 0.1 \text{ moles} \]

### Step 3: Calculate the number of molecules
To find the number of molecules, we use Avogadro's number, which is \( 6.022 \times 10^{23} \) molecules/mol. The formula is:
\[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \]
Substituting the values:
\[ \text{Number of molecules} = 0.1 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mol} \]
Calculating this gives:
\[ \text{Number of molecules} = 6.022 \times 10^{22} \text{ molecules} \]

### Final Answer
The number of molecules present in 4.4 g of \( CO_2 \) gas is \( 6.022 \times 10^{22} \) molecules.

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