If `1.26` grams of oxalic acid is dissolved in 250 ml of solution then its normality is

Options

A. `0.05`
B. `0.04`
C. `0.02`
D. `0.08`

Explanation

To find the normality of the oxalic acid solution, we will follow these steps:

### Step 1: Understand the Formula for Normality
The formula for normality (N) is given by:
\[ N = \frac{\text{Given mass of solute}}{\text{Equivalent weight of solute}} \times \frac{1000}{\text{Volume of solution in mL}} \]

### Step 2: Identify Given Values
From the question, we have:
- Given mass of oxalic acid = 1.26 grams
- Volume of solution = 250 mL

### Step 3: Calculate the Molecular Weight of Oxalic Acid
The molecular formula of oxalic acid is \( H_2C_2O_4 \cdot 2H_2O \).
- The molecular weight can be calculated as follows:
- Hydrogen (H): \( 2 \times 1 = 2 \) g
- Carbon (C): \( 2 \times 12 = 24 \) g
- Oxygen (O): \( 4 \times 16 = 64 \) g
- Water (2H2O): \( 2 \times 18 = 36 \) g
- Total molecular weight = \( 2 + 24 + 64 + 36 = 126 \) g

### Step 4: Determine the n-factor of Oxalic Acid
The n-factor for oxalic acid is the number of protons (H⁺ ions) it can donate. Oxalic acid can donate 2 protons:
- Therefore, n-factor = 2

### Step 5: Calculate the Equivalent Weight of Oxalic Acid
The equivalent weight is calculated using the formula:
\[ \text{Equivalent weight} = \frac{\text{Molecular weight}}{\text{n-factor}} \]
- Equivalent weight = \( \frac{126 \text{ g}}{2} = 63 \text{ g} \)

### Step 6: Calculate Normality
Now we can substitute the values into the normality formula:
\[ N = \frac{1.26 \text{ g}}{63 \text{ g}} \times \frac{1000}{250 \text{ mL}} \]

Calculating this step-by-step:
1. Calculate the fraction:
\[ \frac{1.26}{63} = 0.02 \]
2. Multiply by 1000:
\[ 0.02 \times 1000 = 20 \]
3. Divide by 250:
\[ \frac{20}{250} = 0.08 \]

### Final Answer
The normality of the oxalic acid solution is \( 0.08 \, N \).

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