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3Cu + 8HNO(3) rarr 3Cu (NO(3))(2) +2NO +...

`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

A

`Cu` is oxidized

B

`HNO_(3)` is reduced

C

`Cu` is reduced

D

`Cu` acts as reducing agent

Text Solution

Verified by Experts

The correct Answer is:
C
O.S of Cu increase From oto `+2`
`:.` cu oxidised
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