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12 ml of 0.25 N H(2)SO(4) is neutralised...

12 ml of `0.25 N H_(2)SO_(4)` is neutralised with 15 ml of sodium hydroxide solution on titration, then the normality of NaOH solution is

A

`0.4N`

B

`0.2N`

C

`0.1N`

D

`0.05N`

Text Solution

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The correct Answer is:
B
`N_(1)V_(1) = N_(2)V_(2)`
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