The specific gravity of `H_(2)SO_(4)` is `1.8 g// c c` and this solution is found to contain `98% H_(2)SO_(4)` by weight. `10c c` of this solution is mixed with `350 c c` of pure water. `25 mL `of this dil. `H_(2)SO_(4)` solution neutralises `500 mL` of `NaOH` solution. Then the `P^(H)` of `NaOH` solution is

Options

A. `0.2`
B. `0.5M`
C. `0.1M`
D. `1M`

Answer

B

Explanation

`M = ("Percentage" xx "specific gravity" xx 10)/(GMW)`
`M_(1)V_(1) = M_(2)V_(2)`