Volume `V_(1)mL` of 0.1 M `K_(2)Cr_(2)O_(7)` is needed for complete oxidation of 0.678g `N_(2)H_(4)` in acidic medium. The volume of 0.3M `KMnO_(4)` needed for same oxidation in acidic medium will be :

Options

A. `(2)/(5)V_(1)`
B. `(5)/(2)V_(1)`
C. `113V_(1)`
D. can't say

Answer

A

Explanation

`V_(1)M_(1) xx n_(1) (n-"factor") = V_(2)M_(2) xx n_(2)`
`V_(!) xx 0.1 xx 6 = V_(2) xx 0.3 xx 5`
vol of `KMnO_(4), V_(2) = (2)/(5)V_(1)`