When `100 mL` of an aqueous of `H_(2)O_(2)` is titrated with an excess of `KI` solution in dilute `H_(2)O_(2)`, the liberated `I_(2)` required `50 mL` of `0.1 M Na_(2) S_(2)O_(3)` solution for complete reaction. Calculate the percentage strength and volume strength of `H_(2)O_(2)` solution.

Options

A. `10%`
B. `20%`
C. `5%`
D. `40%`

Answer

A

Explanation

No. of milli equivalents `Cu^(+2) = 100`
`Cu^(+2) = 100 xx 63.5 xx 10^(-3) = 6.35g`
`159.5g` of `CuSO_(4)` should contain `= 63.5g` of copper but only `6.35gCu` is present
% purity `=(6.35)/(63.5) xx 100 = 10%`