A mixture of `H_(2)C_(2)O_(4)` and `K_(2)C_(2)O_(4)` required 0.2 N, 25mL `KMnO_(4)` solution for complete oxidation. Same mixture needs 0.2 M,20 mL NaOH solution for its complete neutralisation. Calculate mole percentage of `H_(2)C_(2)O_(4)` in the given mixture.

Options

A. `90%`
B. `26.8%`
C. `40%`
D. `50%`

Answer

B

Explanation

No. of milli equivalents of `H_(2)C_(2)O_(4) =`No. of milli equivalents of `NaOH = 4`
No. of milli equivalents of
`H_(2)C_(2)O_(4) + Na_(2)C_(2)O_(4) =` No. of milli equivalents of
`KMnO_(4) = 6 xx 0.2 xx 5 = 6` milli equivalents
`Na_(2)C_(2)O_(4) = 2` weight of `Na_(2)C_(2)O_(4)`
`= 2xx 10^(-3) xx 67 = 0.134g`
`% Na_(2)C_(2)O_(4) = (0.134)/(0.5) xx 100 = 26.8`