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Equivalent weight of FeS(2) in the half ...

Equivalent weight of `FeS_(2)` in the half reaction
`FeS rarr Fe_(2)O_(3) + SO_(2)` is :

A

equivalent wt. of `FeS_(2)` is `M//11`

B

the molar ratio of `FeS_(2)` to `O_(2)` is 4:11

C

the molar ratio of `FeS_(2)` to `O_(2)` is `11:4`

D

The molar ratio of `Fe_(2)O` and `SO_(2)` is `1:4`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`4FeS_(2) +11O_(2) rarr 2Fe_(2)O_(3) +8SO_(2)`
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