`x g` of `H_2O_2` requires `100mL` of `M//5 KMnO_4` in a titration in a solution having `pOH = 1.0` Which of the following is`//`are correct?

Options

A. The value of x is `1.7g`
B. The value of x is `0.34g`
C. `MnO_(4)^(-)` changes to `MnO_(4)^(2-)`
D. `H_(2)O_(2)` changes to `O_(2)`

Answer

B, C, D

Explanation

`pOH =1`, strong basic medium
`rArr MnO_(4)^(-) rarr MnO_(4)^(2-)` (n-factor =1)
`2bar(O)H +H_(2)O_(2) rarr O_(2)+2H_(2)O +2e^(-)`
meq of `H_(2)O_(2) =` meq of `MnO_(4)^(-)`
`(x)/(34//2) xx 1000 = 100 xx ((1)/(5)xx1), x = 0.34g`