0.1M solution of KI reacts with excess of `H_(2)SO_(4)` and `KIO_(3)` solutions, according to equation
`5I^(-)+IO_(3)^(-)+6H^(+)to3I^(2)+3H_(2)O`, which of the following statements is /are correct:

Options

A. 200mL of the KI solution react with `0.004` mole `KIO_(3)`
B. 100mL of the KI solution reacts with `0.006` mole of `H_(2)SO_(4)`
C. `0.5` litre of the KI solution produced `0.005` mole of `I_(2)`
D. Equivalent weight of `KIO_(3)` is equal to `(("Molecular weight")/(5))`

Answer

A, B, D

Explanation

`5I^(-) + IO_(3)^(-) + 6H^(+) rarr 3I_(2) +3H_(2)O`
`("Moles of Ki used")/("Moles of" KIO_(3) used) = 5`
Valency factor for `KIO_(3) = 5`
`:. Ew = (M)/(5)`