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Statement Equivalent weight of a species...

Statement Equivalent weight of a species can be written as molecular weight of species divided by valence factor.
Explanation Valence factor represents valence in element, acidity in bases, basicity in acids and total charge on cation or anion in an ionic compound.

A

Statement -1 is True, Statement -2 is True, Statement -2 is a correct

B

Statement -1 is True, Statement -2 is True, statement -2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

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The correct Answer is:
B

`E = (M)/(n-"factor")`
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STATEMENT -1 : Equivalent weight of an acid is always less than its molecular weight. and STATEMENT -2 : Equivalent weight of acid = ("Molecular weight")/("n-factor")

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. The equivalent weight of an element is 13.16 . It forms an acidic oxide which with KOH forms a salt isomorphous with K_(2)SO_(4) . The atomic weight of element is:

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of Fe_(2)O_(3) in terms of its mol. weight in the change Fe_(3)O_(4)rarrFe_(2)O_(3) is

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of N_(2) and NH_(3) in the change N_(2)rarrNH_(3) respectively is:

"The molecule species having same number of atoms and same total number of valence electrons will have similar molecular orbitals and structures" . This is a statement of

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. One mole of As_(2)S_(3) is oxidised by HNO_(3) to H_(3)AsO_(4) and H_(2)SO_(4).HNO_(3) is converted into NO . The moles of HNO_(3) required are:

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. 20 mL 0.2M MnSO_(4) are completely oxidised by 16 mL of KMnO_(4) of unknown normality each forming Mn^(4+) oxidation state. The normality and molarity of KMnO_(4) are respectively:

NARAYNA-SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)-All Questions
  1. 0.1M solution of KI reacts with excess of H(2)SO(4) and KIO(3) solutio...

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  2. 18 " mL of " 1.0 M Br(2) solution undergoes complete disproportionatio...

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  3. Statement Equivalent weight of a species can be written as molecular w...

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  4. Statement-1 : The percentage of nitrogen in Urea is approximately 46.6...

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  5. Statement-1 : Molarity of a solution and molality of a solution both c...

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  6. Statement H(3)PO(3) is a dibasic acid and its salt Na(2)PO(3) does not...

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  7. Statement Addition of water to a solution containing solute and solven...

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  8. Statement Addition of water to a solution containing solute and solven...

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  9. Assertion : The molality of the solution does not change with change i...

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  10. In the reaction, FeS(2)+KMnO(4)+H^(+) to Fe^(3+)+SO(2)+Mn^(2+)+H(2)O...

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  11. Statement H(3)BO(3) is monobasic Lewis acid but its salt Na(3)BO(3) ex...

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  12. Statement 109 % H(2)SO(4) represent a way to express concentration of ...

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  13. consider the following reaction, Na(2)CO(3) + 2HCl to 2NaCl + H(2)O ...

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  14. Direct titration of I(2) with a reducing agent is called iodimetry. If...

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  15. Direct titration of I(2) with a reducing agent is called iodimetry. If...

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  16. To a 25 ml H(2)O(2) solution, excess of acidified solution of Kl was a...

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  17. 25 mL of H(2)O(2) solution were added to excess of acidified solution...

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  18. To a 25 ml H(2)O(2) solution, excess of acidified solution of Kl was a...

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  19. Match the following columns

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  20. Match the following columns

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