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To a 25 ml H(2)O(2) solution, excess of ...

To a 25 ml `H_(2)O_(2)` solution, excess of acidified solution of Kl was added. The iodine liberated required 20 ml of 0.3 N `Na_(2)S_(2)O_(3)` solution.
The volme strength of `H_(2)O_(2)` solution is

A

`11.2ml`

B

`37.2ml`

C

`5.6ml`

D

`22.4ml`

Text Solution

Verified by Experts

The correct Answer is:
C
N' of `20'V' H_(2)O_(2) = 20//5.6`
`V_(1)N_(1) = V_(2)N_(2), V_(1) xx (20)/(5.6) = 200 xx 0.1`
vol. of `H_(2)O_(2)` solution = `5.6 ml`
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