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1.575 g of oxalic acid (CO OH)(2).xH(2)O...

1.575 g of oxalic acid `(CO OH)_(2).xH_(2)O` are dissolved in water and the volume made up to 250 mL. On titration 16.68 mL of this soltuion requires 25 mL of `(N)/(15)NaOH` solution for complete neutralisation. Calculate x.

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The correct Answer is:
2
Meq of oxalic acid in `16.68 mL =` Meq of `NaOH`
`= 25 xx (1)/(15)`
`:.` Meq of oxalic acid in `250mL`
`= 25 xx (1)/(15) xx (250)/(16.68) = 24.98`
`:. (1.575)/((90 +18x)//2) xx 1000 = 24.98 :. x ~~2`
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