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The equilibrium constant of the followin...

The equilibrium constant of the following redox rection at 298 K is `1 xx 10^(8)`
`2Fe^(3+) (aq.) +2I^(-) (aq.) hArr 2Fe^(2+)(aq.) +I_(2) (s)`
If the standard reducing potential of iodine becoming iodide is +0.54 V. what is the standard reduction potential of `Fe^(3+)//Fe^(2+)` ?

A

`64.2`

B

`51.0`

C

`48.4`

D

`25.5`

Text Solution

Verified by Experts

The correct Answer is:
B

No. of equivalent of copper (II) salt =
No. of equivalent of Iodine =No. of equivalents of hypo
`rArr` No. of equivalent of copper (II) salt `= 24.5 xx 0.1 = 2.45`
No. of milli moles of copper (II) salt `=2.45`
Weight of copper in copper (II) salt
`=2.45 xx 63.5 xx 10^(-3) = 0.1556g`
`0.305g` of copper (II) salt contain `=0.1556g` of Cu
`:. %` copper `=(0.1556)/(0.305) xx 100 = 51%`
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