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A 100 ml solution of 0.1 N HCl was titra...

A `100 ml` solution of `0.1 N HCl` was titrated with `0.2`? `N NaOH` solution. The titration. The remaining titration war completed by adding `0.25 N KOH` solution. The volume of `KOH` required for completing the titration is

A

16mL

B

32 mL

C

25 mL

D

8mL

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(a)N_(a) = V_(b)N_(b)`
`100 xx 0.1 = 0.2 xx 30 +0.25 xx V_(2)`
The volume of KOH rected = 16mL
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