A solution of `H_(2)O_(2)` labelled as '20 V' was left open. Due to this some, `H_(2)O_(2)` decomposed and volume strength of the solution decreased . To determine the new volume strength of the `H_(2)O_(2)` solution, 10 mL of the solution was taken and it was diluted to 100 mL . 10 mL of this diluted solution was titrated against 25 mL of 0.0245 M `KMnO_(4)` solution under acidic condition. Calculate the volume strength of the `H_(2)O_(2)` solution .

Options

A. `10V`
B. `5V`
C. `14V`
D. `7V`

Answer

C

Explanation

Normality of diluted `H_(2)O_(2)` solution `=(25 xx 0.02 xx 5)/(10) = 0.25`
Normality of `H_(2)O_(2)` before dilution `=(0.25 xx 100)/(10) = 2.5`
Volume strength of `H_(2)O_(2)` solution `=2.5 xx 5.6 = 14`