20 " mL of " `H_(2)O_(2)` is reacted completely with acidified `K_(2)Cr_(2)O_(7)` solution 40 " mL of " `K_(2)Cr_(3)O_(7)` solution was required to oxidised the `H_(2)O_(2)` completely. Also, 2.0 " mL of " the same `K_(2)Cr_(2)O_(7)` solution required 5.0 " mL of " a 1.0 M `H_(2)C_(2)O_(4)` solution to reach equivalence point. Which of the following statements is/are correct?

Options

A. The `H_(2)O_(2)` solution is 5M
B. The volume strength of `H_(2)O_(2)` is 56V
C. The volume strength of `H_(2)O_(2)` is 112V
D. If 40 mL of `5//8H_(2)O_(2)` is further added to the 10mL of above `H_(2)O_(2)` solution the volume strength of the resulting solution is changed to 16.8V

Answer

A, B, D

Explanation

m.eqts of `C_(2)O_(4)^(2-) -=` m.eqts of `Cr_(2)O_(7)^(2-)`
`5 xx 1.0 xx 2 = N_(2) xx 2`
`:.` Normality of `K_(2)Cr_(2)O_(7) = 5N`
(A) `N xx 20 = 40 xx 5`, Normality of `H_(2)O_(2) = 10`
Molarity of `H_(2)O_(2) = (10)/(2) = 5M`
(B) Volume strength `=N xx 5.6 = 10 xx 5.6 = 56`
(D) Resulting `'M' = (10 xx 5 +40 xx 0.625)/(50) = 1.5M`
Volume strength `= 1.5 xx 11.2 = 16.8V`