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If 216g residue is obtained from 0.5 ml ...


If 216g residue is obtained from 0.5 ml silver salt,

A

`n = 4`

B

`n = 2`

C

Molar mass of salt `=718g//mol`

D

Molar of mass of sat `=388g mol`

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Verified by Experts

The correct Answer is:
B, C
`0.5 xx n = (216)/(108)`mol of `Ag n = 4`
molar mass `=58 +(165) n = 718g//mol`
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