The ion `A^(n+)` is oxidised to `AO_(3)^(-)` by `MnO_(4)^(-)` changing to `Mn^(2+)` in acid medium. Given that `2.68 xx10^(-3)` mole of `A^(n+)` required `1.61 xx10^(-3)` mole of `MnO_(4)^(-)` . What is the value of n.

Options

A. `n =2`
B. Empirical formula of the oxide is AO
C. 1 mole of `A_(2)O_(n)` would require 1 mole of `K_(2)Cr_(2)O_(7)` in acidic medium
D. A' can be a IIA group metal

Answer

A, B, C

Explanation

No of meq of `A_(2)O_(n) =` No of meq of `KMnO_(4)`
`1.34 xx 2 = 2(5-n) = 32.3 xx 0.05 xx 5`