`(26)^2 + (32)^2 + ? = (64)^2` `(1)2246` `(2)2396` `(3)2276` `(4)2386`

2^(3^2) = (a)64 (b) 32 (c)256 (d) 512

Simplify (32)^(1//5)+ (-7)^(0) + (64)^(1//2)

If (16)^(2x+3)=(64)^(x+3), then 4^(2x-2)=64(b)256(c)32(d)512

(sin ^ (2) [64]) / (cos ^ (2) [26]) =?

1+(4)/(1!)+(16)/(2!)+(64)/(3!)+....=

2, 5, 10, 17, 26, 37; 50, 64 (a) 50 (b) 26 (c) 37 (d) 64

(1/64)^(0)+(64)^(-1/2)+(32)^(4/5)-(32)^(-4/5)=?

1+(3+1)(3^(2)+1)(3^(4)+1)(3^(8)+1)(3^(16)+1)(3^(32)+1) is equal to (3^(64)-1)/(2) b.(3^(64)+1)/(2) c.3^(64)-1 d.3^(64)+1

Evaluate (i) (32)^((1)/(5)) +(-7)^(0) + (64)^((1)/(2)) (ii) (0.00032)^(-(2)/(3)) (iii) ((64)/(125))^(-(2)/(3)) .

If (16)^(2x+3)=(64)^(x+3), then 4^(2x-2)= (a) 64 (b) 256 (c) 32 (d) 512