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{x in RR:(2x-1)/(x^(3)+4x^(2)+3x) in RR}...

`{x in RR:(2x-1)/(x^(3)+4x^(2)+3x) in RR}=`

A

`RR-{0}`

B

`RR-{0, 1,3}`

C

`RR-{0, -1, -3}`

D

`RR-{0, -1, -3, +1//2}`

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The correct Answer is:
3
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