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First and second ionization energies of ...

First and second ionization energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ/mol needed to convert all the atoms of Magnesium into `Mg^(2+)` ions present in 12 mg of magnesium vapours is: (Report your answer by multiplying with 10 and round it upto nearest integer)
(Given `1 eV = 96.5 kJ mol^(-1))`

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First and second ionisation energies of magnesium are 5.7 and 15.035eV respectively. The amount of energy in kJ needed to convert all the atoms of magnesium into Mg^(+2) ions present in 12mg of magnesium vapour is [1eV=96.5kJ " mol"^(-1) ]

First and second ionisation energies of magnesium are 7.646 eV and 15.035ev respectively. The amount of energy in kJ needed to convert all the atoms of magnesium intp Mg^(2+) ions present in 12 mg of magnesium vapour will be? [Given 1 eV = 96.5 kJ ml^(-1)]

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