The time period of a simple pendulum mea...

The time period of a simple pendulum measured inside a stationary lift is found to be T . If the lift starts accelerating upwards with an acceleration `g //3`, the time period is

A

`sqrt(2)T`

B

`(T)/(sqrt(2))`

C

`(sqrt(3))/(2)T`

D

`(T)/(3)`

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The correct Answer is:

C

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