The volume percentage of Cl2 at equilibr...

The volume percentage of `Cl_2` at equilibrium in the dissociation of `PCl_5` under a total pressure of 1.5atm is (Kp = 0.202) ,

74.5

36.5

63.5

26.6

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Calculate the volume percent of chlorine gas at equilibrium in the dissociation of PCl_(5)(g) under a total pressure of 1.5 atm. The K_(p) for its dissociation =0.3 .

Why does the dissociation of PCl_5 decrease in the presence of Cl_2 ?

Assertion : In the dissociation of PCl_(5) at constant pressure and temperature addition of helium at equilibrium increases the dissociation of PCl_(5) . Reason : Helium reacts with Cl_(2) and hence shifts the equilibrium in forward direction.

Phosphorus pentachloride dissociates as follows in a closed reaction vessel. PCl_5(g) hArr PCl_3(g) +Cl_2(g) If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be:

0.1 mol of PCl_(5) is vaporised in a litre vessel at 260^(@)C . Calculate the concentration of Cl_(2) at equilibrium, if the equilibrium constant for the dissociation of PCl_(5) is 0.0414 .

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