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Specific conductance of 0.1 MHA is 3.75x...

Specific conductance of 0.1 MHA is `3.75xx10^(-4)ohm^(-1)cm^(-1)`. If `lamda^(oo)` of HA is `250 ohm^(-1)cm^2mol^(-1)`, then dissociation constant `K_a` of HA is

A

`1xx10^(-5)`

B

`2.25xx10^(-4)`

C

`2.25xx10^(-13)`

D

`2.25xx10^(-13)`

Text Solution

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The correct Answer is:
C
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