[" If "m=sin theta+cos theta" and "n=sec theta+cos],[" prove that "n(m+1)(m-1)=2m]

If m= sin theta+ cos theta and n= sec theta+cosec theta , prove that n (m + 1) (m-1) = 2m .

If sin theta+cos theta=m and sec theta+cos ec theta=n then n(m+1)(m-1) equals

If sin theta + cos theta = m and sec theta + "cosec" theta = n, prove that n(m^(2)-1) = 2m.

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals

If sin theta + cos theta = m and sec theta + " cosec " theta = n then

If sin theta + cos thea = m and sec theta+ cosec theta = n , then n (m + 1) (m - 1) =

If sintheta +cos theta =m and sec theta + cosec theta =n then n(m+1)(m-1) equals................ A) m B) n C) 2m D) 2n

If cos ec theta+cot theta=m and cos ec theta-cot theta=n, prove that mn=1

If sin theta + costheta = m and sin theta - cos theta = n , then