`[16^(-1/5)]^(5/2)`

Simplify each of the following: (i) (16)^((1)/(5))xx(2)^((1)/(5)) (ii) ((243)^((1)/(4)))/((3)^((1)/(4)))

Simplify each of the following: (i) (16)^(1/5)xx(2)^(1/5) (ii) (243)^(1/ 4)/(3)^(1/ 4)

(16^(-1)xx5^(3))/(2^(-4))

A B C is an isosceles triangle. If the coordinates of the base are B(1,3) and C(-2,7) , the coordinates of vertex A can be (1,6) (b) (-1/2,5) (5/6,6) (d) none of these

ABC is an isosceles triangle.If the coordinates of the base are B(1,3) and C(-2,7), the coordinates of vertex A can be (1,6)( b) (-(1)/(2),5)((5)/(6),6) (d) none of these

Show that (16(32^(x))-2^(3x-2)*4^(x+1))/(15*2^(x-1)*16^(x))-(5*5^(x-1))/(sqrt(5^(2x))) is given

Sin^(-1)(16/65)+2Tan^(-1)(1/5)=

If the surm of the first ten terms of the series, (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+........ , is 16/5m ,then m is equal to

If the surm of the first ten terms of the series,(1(3)/(5))^(2)+(2(2)/(5))^(2)+(3(1)/(5))^(2)+4^(2)+(4(4)/(5))^(2)+ is (16)/(5)m, then m is equal to