`(dy)/(dx)=y+int_0^1 ydx` given y=1 where x=0

If the solution of differential equation (dy)/(dx)=y+int_(0)^(1)ydx, given y=1 when x=0 is y=(1)/(3-e)(Ae^(x)+Be+1) then find the value of A+B.

Solve the differential equation (dy)/(dx) = y + int_(0)^(1)y(x)dx , given that the value of y is 1, when x = 0.

Solve the differential equation (dy)/(dx) = y + int_(0)^(1)y(x)dx , given that the value of y is 1 , when x = 0 .

Solve (x-y)(dx+dy)=dx-dy , given that y=-1 , where x=0 .

Solve (x-y)(dx+dy)=dx-dy , given that y=-1 , where x=0 .

Find the particular solution of (x-y)(dx+dy)=dx-dy, given y=1, when x=0

Find the particular solution of y(1-x^2)(dy)/(dx)+x(1-y^2)=0 , given that y=0 when x=0

Let a function y=f(x) satisfies the following conditions : 1.(dy)/(dx)=y+int_(0)^(1)ydx2.f(0)=1 then equal to f'(0)

int_(0)^(1)y dx where x=cos2y

Solve the differential equation ( x + y) dy + (x - y) dx = 0 ; given that y = 1 when x = 1.