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If sin theta + cos theta = m, show that ...

If sin `theta` + cos `theta` = m, show that
`cos^(6)theta + sin^(6)theta = (4 - 3(m^(2) - 1)^(2))/(4)` where `m^(2) le 2`.

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The correct Answer is:
1 - 3 `sin^(2) theta cos^(2) theta`
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