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Prove that sin 4alpha = 4 tan alpha (1 -...

Prove that sin `4alpha = 4 tan alpha (1 - tan^(2) alpha)/((1 + tan^(2) alpha)^(2))`

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The correct Answer is:
`4 tan alpha. (1 - tan^(2) alpha)/((1 + tan^(2) alpha)^(2))`
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