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If a(ij)=(1)/(2) (3i-2j) and A = [a(ij)]...

If `a_(ij)=(1)/(2) (3i-2j) and A = [a_(ij)]_(2xx2)` is

A

`[((1)/(2),2),(-(1)/(2),1)]`

B

`[((1)/(2),-(1)/(2)),(2,1)]`

C

`[(2,2),((1)/(2),-(1)/(2))]`

D

`[(-(1)/(2),(1)/(2)),(1,2)]`

Text Solution

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The correct Answer is:
A, B
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