Let `vec a` and `vec b` be the position vectors of the points A and B. Prove that the position vectors of the points which trisects the line segment AB are `(veca+2vecb)/(3)and (vecb+2veca)/(3)`.

If veca and vecb are position vectors of A and B respectively, then the position vector of a point C in vec(AB) produced such that vec(AC) =2015 vec(AB) is

If veca,vecb are the position vectors A and B then which one of the following points whose position vector lies on AB, is

Let veca,vecb and vecc be non-coplanar vectors. Let A,B and C be the points whose position vectors with respect to the origin O are veca+2vecb+3vecc,-2veca+3vecb+5vecc and 7veca-vecc respectively. Then prove that A, B and C are collinear.

If veca, vecb, vecc, vecd are the position vectors of points A, B, C and D , respectively referred to the same origin O such that no three of these points are collinear and veca+vecc=vecb+vecd , then prove that quadrilateral ABCD is a parallelogram.

Let O be the origin . Let A and B be two points whose position vectors are veca and vecb .Then the position vector of a point P which divides AB internally in the ratio l:m is:

Let veca and vec b be two unit vectors such that angle between them is 60^(@) .Then |veca - vec b| is equal to

The position vectors veca,vecb,vecc of three points satisfy the relation 2veca-7vecb+5vecc=vec0. Are these points collinear?

If vecr=(5veca-3vecb)/2 , then the point P whose position vector r divides the line joining the points with position vectors vec and vecb in the ratio: