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30 sec (2 - 15 x) tan (2 - 15 x)...

30 sec (2 - 15 x) tan (2 - 15 x)

Text Solution

Verified by Experts

The correct Answer is:
`= overset(2)cancel(30)(sec(2 - 15 x))/(- cancel(15))+c = - 2 sec (2 - 15 x) + c `
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