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The value of 1/(2!)+1/(4!)+1/(6!)+... is...

The value of `1/(2!)+1/(4!)+1/(6!)+...` is

A

`(e^(2)+1)/(2e)

B

`((e+1)^(2))/(2e)`

C

`((e-1)^(2))/(2e)`

D

`(e^(2)+1)/(2e)`

Text Solution

Verified by Experts

The correct Answer is:
A, B
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