A sample of gas at `15^(@)C` at 1 atm has a volume of `2.58dm^(3)`. When the temperature is raised to `38^(@)C` at 1 atm does the volume of the gas increase? If so, calculate the final volume.

Explanation

`T_(1)=15^(@)C+273,T_(2)=38+273`
`T_(1)=238K" "T_(2)=311K`
`V_(1)=2.58dm^(3)" "V_(2)=?`
(P=1 atm constant)
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`V_(2)=((V_(1))/(T_(1)))xxT_(2)=(2.58dm^(3))/(288cancel(K))xx311cancel(K)`
`V_(2)=2.78dm^(3)` i.e. volume increased from `2.58dm^(2)` to `2.78dm^(3)`.